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1340131124441 = 6192164993739
BaseRepresentation
bin10011100000000110000…
…010100010010011011001
311202010010001010210122102
4103200012002202103121
5133424042031440231
62503351524533145
7165551461415234
oct23400602422331
94663101123572
101340131124441
1147738a09aa3a
121978872511b5
13994b239a215
1448c1132a41b
1524cd71adacb
hex138060a24d9

1340131124441 has 4 divisors (see below), whose sum is σ = 1342296118800. Its totient is φ = 1337966130084.

The previous prime is 1340131124417. The next prime is 1340131124443. The reversal of 1340131124441 is 1444211310431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340131124441 - 234 = 1322951255257 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340131124443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1082496251 + ... + 1082497488.

It is an arithmetic number, because the mean of its divisors is an integer number (335574029700).

Almost surely, 21340131124441 is an apocalyptic number.

It is an amenable number.

1340131124441 is a deficient number, since it is larger than the sum of its proper divisors (2164994359).

1340131124441 is an equidigital number, since it uses as much as digits as its factorization.

1340131124441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2164994358.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 1340131124441 its reverse (1444211310431), we get a palindrome (2784342434872).

The spelling of 1340131124441 in words is "one trillion, three hundred forty billion, one hundred thirty-one million, one hundred twenty-four thousand, four hundred forty-one".

Divisors: 1 619 2164993739 1340131124441