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134013121433017 is a prime number
BaseRepresentation
bin11110011110001001011100…
…011111111000110110111001
3122120111112021211222211221121
4132132021130133320312321
5120031132333041324032
61153004440021505241
740141062036102421
oct3636113437706671
9576445254884847
10134013121433017
1139778711374712
1213044783272221
1359a14c995b868
1425143ac037481
151075ec7490a97
hex79e25c7f8db9

134013121433017 has 2 divisors, whose sum is σ = 134013121433018. Its totient is φ = 134013121433016.

The previous prime is 134013121432963. The next prime is 134013121433041. The reversal of 134013121433017 is 710334121310431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101042281816441 + 32970839616576 = 10051979^2 + 5742024^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134013121433017 is a prime.

It is not a weakly prime, because it can be changed into another prime (134013121433057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006560716508 + 67006560716509.

It is an arithmetic number, because the mean of its divisors is an integer number (67006560716509).

Almost surely, 2134013121433017 is an apocalyptic number.

It is an amenable number.

134013121433017 is a deficient number, since it is larger than the sum of its proper divisors (1).

134013121433017 is an equidigital number, since it uses as much as digits as its factorization.

134013121433017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 34.

Adding to 134013121433017 its reverse (710334121310431), we get a palindrome (844347242743448).

The spelling of 134013121433017 in words is "one hundred thirty-four trillion, thirteen billion, one hundred twenty-one million, four hundred thirty-three thousand, seventeen".