134013121433041 has 2 divisors, whose sum is σ = 134013121433042. Its totient is φ = 134013121433040.

The previous prime is 134013121433017. The next prime is 134013121433057. The reversal of 134013121433041 is 140334121310431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92100393641025 + 41912727792016 = 9596895^2 + 6474004^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134013121433041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134013121432994 and 134013121433012.

It is not a weakly prime, because it can be changed into another prime (134013121433141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006560716520 + 67006560716521.

It is an arithmetic number, because the mean of its divisors is an integer number (67006560716521).

Almost surely, 2^{134013121433041} is an apocalyptic number.

It is an amenable number.

134013121433041 is a deficient number, since it is larger than the sum of its proper divisors (1).

134013121433041 is an equidigital number, since it uses as much as digits as its factorization.

134013121433041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 134013121433041 its reverse (140334121310431), we get a palindrome (274347242743472).

The spelling of 134013121433041 in words is "one hundred thirty-four trillion, thirteen billion, one hundred twenty-one million, four hundred thirty-three thousand, forty-one".