134013121433102 has 4 divisors (see below), whose sum is σ = 201019682149656. Its totient is φ = 67006560716550.

The previous prime is 134013121433083. The next prime is 134013121433117. The reversal of 134013121433102 is 201334121310431.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×134013121433102² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33503280358274 + ... + 33503280358277.

It is an arithmetic number, because the mean of its divisors is an integer number (50254920537414).

Almost surely, 2^{134013121433102} is an apocalyptic number.

134013121433102 is a deficient number, since it is larger than the sum of its proper divisors (67006560716554).

134013121433102 is an equidigital number, since it uses as much as digits as its factorization.

134013121433102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67006560716553.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 134013121433102 its reverse (201334121310431), we get a palindrome (335347242743533).

The spelling of 134013121433102 in words is "one hundred thirty-four trillion, thirteen billion, one hundred twenty-one million, four hundred thirty-three thousand, one hundred two".