Base | Representation |
---|---|
bin | 11110011110001001100111… |
… | …001100110011001010100111 |
3 | 122120111112202100211200211111 |
4 | 132132021213030303022213 |
5 | 120031133220022301333 |
6 | 1153004505514045451 |
7 | 40141066346155243 |
oct | 3636114714631247 |
9 | 576445670750744 |
10 | 134013300978343 |
11 | 397787a3756786 |
12 | 13044813419887 |
13 | 59a1527c037b7 |
14 | 25143c7c13423 |
15 | 1075ed81094cd |
hex | 79e2673332a7 |
134013300978343 has 2 divisors, whose sum is σ = 134013300978344. Its totient is φ = 134013300978342.
The previous prime is 134013300978317. The next prime is 134013300978383. The reversal of 134013300978343 is 343879003310431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134013300978343 - 213 = 134013300970151 is a prime.
It is a super-2 number, since 2×1340133009783432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134013300978383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006650489171 + 67006650489172.
It is an arithmetic number, because the mean of its divisors is an integer number (67006650489172).
Almost surely, 2134013300978343 is an apocalyptic number.
134013300978343 is a deficient number, since it is larger than the sum of its proper divisors (1).
134013300978343 is an equidigital number, since it uses as much as digits as its factorization.
134013300978343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 49.
The spelling of 134013300978343 in words is "one hundred thirty-four trillion, thirteen billion, three hundred million, nine hundred seventy-eight thousand, three hundred forty-three".
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