134013301011127 has 2 divisors, whose sum is σ = 134013301011128. Its totient is φ = 134013301011126.

The previous prime is 134013301011049. The next prime is 134013301011143. The reversal of 134013301011127 is 721110103310431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134013301011127 - 2¹⁹ = 134013300486839 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134013301011095 and 134013301011104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134013301011427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006650505563 + 67006650505564.

It is an arithmetic number, because the mean of its divisors is an integer number (67006650505564).

Almost surely, 2^{134013301011127} is an apocalyptic number.

134013301011127 is a deficient number, since it is larger than the sum of its proper divisors (1).

134013301011127 is an equidigital number, since it uses as much as digits as its factorization.

134013301011127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 28.

Adding to 134013301011127 its reverse (721110103310431), we get a palindrome (855123404321558).

The spelling of 134013301011127 in words is "one hundred thirty-four trillion, thirteen billion, three hundred one million, eleven thousand, one hundred twenty-seven".