13401420441133 has 2 divisors, whose sum is σ = 13401420441134. Its totient is φ = 13401420441132.

The previous prime is 13401420441089. The next prime is 13401420441139. The reversal of 13401420441133 is 33114402410431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7269348845929 + 6132071595204 = 2696173^2 + 2476302^2 .

It is a cyclic number.

It is not a de Polignac number, because 13401420441133 - 2⁹ = 13401420440621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13401420441095 and 13401420441104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401420441139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700710220566 + 6700710220567.

It is an arithmetic number, because the mean of its divisors is an integer number (6700710220567).

Almost surely, 2^{13401420441133} is an apocalyptic number.

It is an amenable number.

13401420441133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401420441133 is an equidigital number, since it uses as much as digits as its factorization.

13401420441133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13401420441133 its reverse (33114402410431), we get a palindrome (46515822851564).

The spelling of 13401420441133 in words is "thirteen trillion, four hundred one billion, four hundred twenty million, four hundred forty-one thousand, one hundred thirty-three".