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134014221443 = 439887315223
BaseRepresentation
bin111110011001111011…
…1101011110010000011
3110210220200101211020002
41330303313223302003
54143430120041233
6141322033510215
712452666041604
oct1746367536203
9423820354202
10134014221443
1151920597113
1221b8111236b
13c8397353ab
1466b4681dab
1537454976e8
hex1f33debc83

134014221443 has 8 divisors (see below), whose sum is σ = 137145136128. Its totient is φ = 130883957064.

The previous prime is 134014221437. The next prime is 134014221499. The reversal of 134014221443 is 344122410431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134014221443 - 216 = 134014155907 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134014221043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 267530 + ... + 582752.

It is an arithmetic number, because the mean of its divisors is an integer number (17143142016).

Almost surely, 2134014221443 is an apocalyptic number.

134014221443 is a deficient number, since it is larger than the sum of its proper divisors (3130914685).

134014221443 is an equidigital number, since it uses as much as digits as its factorization.

134014221443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 325153.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 134014221443 its reverse (344122410431), we get a palindrome (478136631874).

The spelling of 134014221443 in words is "one hundred thirty-four billion, fourteen million, two hundred twenty-one thousand, four hundred forty-three".

Divisors: 1 43 9887 315223 425141 13554589 3116609801 134014221443