Base | Representation |
---|---|
bin | 11000111101100100… |
… | …10111101010111001 |
3 | 1021120222010210122021 |
4 | 30132302113222321 |
5 | 204421231010041 |
6 | 10053450554441 |
7 | 653046132454 |
oct | 143662275271 |
9 | 37528123567 |
10 | 13401422521 |
11 | 5757832103 |
12 | 2720138a21 |
13 | 13575c0916 |
14 | 911bc049b |
15 | 5367e6cd1 |
hex | 31ec97ab9 |
13401422521 has 2 divisors, whose sum is σ = 13401422522. Its totient is φ = 13401422520.
The previous prime is 13401422519. The next prime is 13401422539. The reversal of 13401422521 is 12522410431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13119182521 + 282240000 = 114539^2 + 16800^2 .
It is an emirp because it is prime and its reverse (12522410431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13401422521 - 21 = 13401422519 is a prime.
Together with 13401422519, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13401422621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700711260 + 6700711261.
It is an arithmetic number, because the mean of its divisors is an integer number (6700711261).
Almost surely, 213401422521 is an apocalyptic number.
It is an amenable number.
13401422521 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401422521 is an equidigital number, since it uses as much as digits as its factorization.
13401422521 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 13401422521 its reverse (12522410431), we get a palindrome (25923832952).
The spelling of 13401422521 in words is "thirteen billion, four hundred one million, four hundred twenty-two thousand, five hundred twenty-one".
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