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13401430251 = 3112571580171
BaseRepresentation
bin11000111101100100…
…11001100011101011
31021120222011012020120
430132302121203223
5204421231232001
610053451054323
7653046164136
oct143662314353
937528135216
1013401430251
1157578379a0
1227201413a3
1313575c42b1
14911bc321d
155367e9236
hex31ec998eb

13401430251 has 16 divisors (see below), whose sum is σ = 19568850048. Its totient is φ = 8090470400.

The previous prime is 13401430247. The next prime is 13401430277. The reversal of 13401430251 is 15203410431.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 13401430251 - 22 = 13401430247 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13401430201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 781605 + ... + 798566.

It is an arithmetic number, because the mean of its divisors is an integer number (1223053128).

Almost surely, 213401430251 is an apocalyptic number.

13401430251 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13401430251 is a deficient number, since it is larger than the sum of its proper divisors (6167419797).

13401430251 is a wasteful number, since it uses less digits than its factorization.

13401430251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1580442.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 13401430251 its reverse (15203410431), we get a palindrome (28604840682).

The spelling of 13401430251 in words is "thirteen billion, four hundred one million, four hundred thirty thousand, two hundred fifty-one".

Divisors: 1 3 11 33 257 771 2827 8481 1580171 4740513 17381881 52145643 406103947 1218311841 4467143417 13401430251