Base | Representation |
---|---|
bin | 111110011001111100… |
… | …0011000001000111011 |
3 | 110210220200202001110021 |
4 | 1330303320120020323 |
5 | 4143430141400011 |
6 | 141322041431311 |
7 | 12453000426400 |
oct | 1746370301073 |
9 | 423820661407 |
10 | 134014403131 |
11 | 51920700674 |
12 | 21b8119b537 |
13 | c839799cbb |
14 | 66b46cc2a7 |
15 | 37454d1471 |
hex | 1f33e1823b |
134014403131 has 6 divisors (see below), whose sum is σ = 155894305740. Its totient is φ = 114869488356.
The previous prime is 134014403101. The next prime is 134014403137. The reversal of 134014403131 is 131304410431.
It is a happy number.
It is not a de Polignac number, because 134014403131 - 29 = 134014402619 is a prime.
It is a super-2 number, since 2×1340144031312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 134014403096 and 134014403105.
It is not an unprimeable number, because it can be changed into a prime (134014403137) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1367493861 + ... + 1367493958.
It is an arithmetic number, because the mean of its divisors is an integer number (25982384290).
Almost surely, 2134014403131 is an apocalyptic number.
134014403131 is a deficient number, since it is larger than the sum of its proper divisors (21879902609).
134014403131 is an equidigital number, since it uses as much as digits as its factorization.
134014403131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2734987833 (or 2734987826 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 134014403131 its reverse (131304410431), we get a palindrome (265318813562).
The spelling of 134014403131 in words is "one hundred thirty-four billion, fourteen million, four hundred three thousand, one hundred thirty-one".
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