Base | Representation |
---|---|
bin | 1100001100000100101010… |
… | …1000111010101000011110 |
3 | 1202110011202002001101120212 |
4 | 3003001022220322220132 |
5 | 3224032333323002142 |
6 | 44300330455012422 |
7 | 2552141623123043 |
oct | 303011250725036 |
9 | 52404662041525 |
10 | 13401550203422 |
11 | 42a7624791947 |
12 | 160538806a112 |
13 | 7629b7515894 |
14 | 3448d20391ca |
15 | 1839121e4d82 |
hex | c304aa3aa1e |
13401550203422 has 4 divisors (see below), whose sum is σ = 20102325305136. Its totient is φ = 6700775101710.
The previous prime is 13401550203421. The next prime is 13401550203491. The reversal of 13401550203422 is 22430205510431.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13401550203421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3350387550854 + ... + 3350387550857.
It is an arithmetic number, because the mean of its divisors is an integer number (5025581326284).
Almost surely, 213401550203422 is an apocalyptic number.
13401550203422 is a deficient number, since it is larger than the sum of its proper divisors (6700775101714).
13401550203422 is an equidigital number, since it uses as much as digits as its factorization.
13401550203422 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6700775101713.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 13401550203422 its reverse (22430205510431), we get a palindrome (35831755713853).
The spelling of 13401550203422 in words is "thirteen trillion, four hundred one billion, five hundred fifty million, two hundred three thousand, four hundred twenty-two".
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