Base | Representation |
---|---|
bin | 111110011010000000… |
… | …1000000011111001111 |
3 | 110210220211222222220121 |
4 | 1330310001000133033 |
5 | 4143431231244201 |
6 | 141322202125411 |
7 | 12453025601356 |
oct | 1746401003717 |
9 | 423824888817 |
10 | 134016665551 |
11 | 51921a0643a |
12 | 21b81ab0867 |
13 | c83a0aca02 |
14 | 66b4b1a99d |
15 | 37457cb9a1 |
hex | 1f340407cf |
134016665551 has 2 divisors, whose sum is σ = 134016665552. Its totient is φ = 134016665550.
The previous prime is 134016665479. The next prime is 134016665557. The reversal of 134016665551 is 155566610431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134016665551 - 29 = 134016665039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134016665498 and 134016665507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134016665557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67008332775 + 67008332776.
It is an arithmetic number, because the mean of its divisors is an integer number (67008332776).
Almost surely, 2134016665551 is an apocalyptic number.
134016665551 is a deficient number, since it is larger than the sum of its proper divisors (1).
134016665551 is an equidigital number, since it uses as much as digits as its factorization.
134016665551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324000, while the sum is 43.
The spelling of 134016665551 in words is "one hundred thirty-four billion, sixteen million, six hundred sixty-five thousand, five hundred fifty-one".
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