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13402000433 = 232113275767
BaseRepresentation
bin11000111101101001…
…00100110000110001
31021121000020011101102
430132310210300301
5204421403003213
610053511214145
7653054060363
oct143664446061
937530204342
1013402000433
115758097318
122720377355
131357763993
14911cd0d33
155368ad158
hex31ed24c31

13402000433 has 8 divisors (see below), whose sum is σ = 13991365248. Its totient is φ = 12813191424.

The previous prime is 13402000393. The next prime is 13402000453. The reversal of 13402000433 is 33400020431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13402000433 - 212 = 13401996337 is a prime.

It is a super-2 number, since 2×134020004332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13402000453) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 89285 + ... + 186482.

It is an arithmetic number, because the mean of its divisors is an integer number (1748920656).

Almost surely, 213402000433 is an apocalyptic number.

It is an amenable number.

13402000433 is a deficient number, since it is larger than the sum of its proper divisors (589364815).

13402000433 is a wasteful number, since it uses less digits than its factorization.

13402000433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 277903.

The product of its (nonzero) digits is 864, while the sum is 20.

Adding to 13402000433 its reverse (33400020431), we get a palindrome (46802020864).

The spelling of 13402000433 in words is "thirteen billion, four hundred two million, four hundred thirty-three", and thus it is an aban number.

Divisors: 1 23 2113 48599 275767 6342641 582695671 13402000433