1340200141 has 4 divisors (see below), whose sum is σ = 1531657312. Its totient is φ = 1148742972.

The previous prime is 1340200123. The next prime is 1340200177. The reversal of 1340200141 is 1410020431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1410020431 = 17401 ⋅81031.

It is a cyclic number.

It is not a de Polignac number, because 1340200141 - 2⁵ = 1340200109 is a prime.

It is a super-2 number, since 2×1340200141² = 3592272835872839762, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340206141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95728575 + ... + 95728588.

It is an arithmetic number, because the mean of its divisors is an integer number (382914328).

Almost surely, 2^1340200141 is an apocalyptic number.

It is an amenable number.

1340200141 is a deficient number, since it is larger than the sum of its proper divisors (191457171).

1340200141 is an equidigital number, since it uses as much as digits as its factorization.

1340200141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 191457170.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 1340200141 is about 36608.7440511143. The cubic root of 1340200141 is about 1102.5286568275.

Adding to 1340200141 its reverse (1410020431), we get a palindrome (2750220572).

The spelling of 1340200141 in words is "one billion, three hundred forty million, two hundred thousand, one hundred forty-one".