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13402002325 = 52536080093
BaseRepresentation
bin11000111101101001…
…00101001110010101
31021121000020020222111
430132310211032111
5204421403033300
610053511231021
7653054066035
oct143664451625
937530206874
1013402002325
115758098788
122720378471
1313577647ba
14911cd18c5
155368ad9ba
hex31ed25395

13402002325 has 6 divisors (see below), whose sum is σ = 16618482914. Its totient is φ = 10721601840.

The previous prime is 13402002311. The next prime is 13402002331. The reversal of 13402002325 is 52320020431.

It can be written as a sum of positive squares in 3 ways, for example, as 2116552036 + 11285450289 = 46006^2 + 106233^2 .

It is not a de Polignac number, because 13402002325 - 215 = 13401969557 is a prime.

It is a super-2 number, since 2×134020023252 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13402002296 and 13402002305.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 268040022 + ... + 268040071.

Almost surely, 213402002325 is an apocalyptic number.

It is an amenable number.

13402002325 is a deficient number, since it is larger than the sum of its proper divisors (3216480589).

13402002325 is an equidigital number, since it uses as much as digits as its factorization.

13402002325 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 536080103 (or 536080098 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 22.

Adding to 13402002325 its reverse (52320020431), we get a palindrome (65722022756).

The spelling of 13402002325 in words is "thirteen billion, four hundred two million, two thousand, three hundred twenty-five".

Divisors: 1 5 25 536080093 2680400465 13402002325