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13402003310030 = 253096294328407
BaseRepresentation
bin1100001100000110010110…
…1001011000010111001110
31202110012220122122121000002
43003001211221120113032
53224034300321410110
644300443442404302
72552156064351416
oct303014551302716
952405818577002
1013402003310030
1142a783752a615
121605493960692
13762a5a35c5ba
143449362a5646
1518393bd98aa5
hexc3065a585ce

13402003310030 has 16 divisors (see below), whose sum is σ = 24123689442720. Its totient is φ = 5360782771872.

The previous prime is 13402003310029. The next prime is 13402003310041. The reversal of 13402003310030 is 3001330020431.

It is a super-2 number, since 2×134020033100302 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13402003309984 and 13402003310011.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 932087 + ... + 5260493.

It is an arithmetic number, because the mean of its divisors is an integer number (1507730590170).

Almost surely, 213402003310030 is an apocalyptic number.

13402003310030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13402003310030 is a deficient number, since it is larger than the sum of its proper divisors (10721686132690).

13402003310030 is a wasteful number, since it uses less digits than its factorization.

13402003310030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4638043.

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 13402003310030 its reverse (3001330020431), we get a palindrome (16403333330461).

The spelling of 13402003310030 in words is "thirteen trillion, four hundred two billion, three million, three hundred ten thousand, thirty".

Divisors: 1 2 5 10 309629 619258 1548145 3096290 4328407 8656814 21642035 43284070 1340200331003 2680400662006 6701001655015 13402003310030