Base | Representation |
---|---|
bin | 111110011010000111… |
… | …0001110010111101001 |
3 | 110210221002112000121221 |
4 | 1330310032032113221 |
5 | 4143433123132111 |
6 | 141322404302041 |
7 | 12453100211542 |
oct | 1746416162751 |
9 | 423832460557 |
10 | 134020130281 |
11 | 51923962554 |
12 | 21b830a1921 |
13 | c83aa23a4b |
14 | 66b537d4c9 |
15 | 3745c63371 |
hex | 1f3438e5e9 |
134020130281 has 2 divisors, whose sum is σ = 134020130282. Its totient is φ = 134020130280.
The previous prime is 134020130243. The next prime is 134020130327. The reversal of 134020130281 is 182031020431.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 121005883881 + 13014246400 = 347859^2 + 114080^2 .
It is a cyclic number.
It is not a de Polignac number, because 134020130281 - 29 = 134020129769 is a prime.
It is a super-2 number, since 2×1340201302812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134020130681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010065140 + 67010065141.
It is an arithmetic number, because the mean of its divisors is an integer number (67010065141).
Almost surely, 2134020130281 is an apocalyptic number.
It is an amenable number.
134020130281 is a deficient number, since it is larger than the sum of its proper divisors (1).
134020130281 is an equidigital number, since it uses as much as digits as its factorization.
134020130281 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
The spelling of 134020130281 in words is "one hundred thirty-four billion, twenty million, one hundred thirty thousand, two hundred eighty-one".
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