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13402020000130 = 251559859654907
BaseRepresentation
bin1100001100000110011010…
…1001000011000110000010
31202110012221211001112111221
43003001212221003012002
53224034314110001010
644300445240225254
72552156356253536
oct303014651030602
952405854045457
1013402020000130
1142a784599a093
12160549946b22a
13762a609542b8
143449385abbc6
1518393d593dda
hexc3066a43182

13402020000130 has 16 divisors (see below), whose sum is σ = 24139109816640. Its totient is φ = 5357369374192.

The previous prime is 13402020000121. The next prime is 13402020000137. The reversal of 13402020000130 is 3100002020431.

It is a happy number.

It is a super-2 number, since 2×134020200001302 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13402020000137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 429811864 + ... + 429843043.

It is an arithmetic number, because the mean of its divisors is an integer number (1508694363540).

Almost surely, 213402020000130 is an apocalyptic number.

13402020000130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13402020000130 is a deficient number, since it is larger than the sum of its proper divisors (10737089816510).

13402020000130 is a wasteful number, since it uses less digits than its factorization.

13402020000130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 859656473.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 13402020000130 its reverse (3100002020431), we get a palindrome (16502022020561).

The spelling of 13402020000130 in words is "thirteen trillion, four hundred two billion, twenty million, one hundred thirty", and thus it is an aban number.

Divisors: 1 2 5 10 1559 3118 7795 15590 859654907 1719309814 4298274535 8596549070 1340202000013 2680404000026 6701010000065 13402020000130