Base | Representation |
---|---|
bin | 11110011110010000000010… |
… | …011010011111010110111100 |
3 | 122120112012120011120110111101 |
4 | 132132100002122133112330 |
5 | 120031241332200044004 |
6 | 1153012010244102444 |
7 | 40141432331000620 |
oct | 3636200232372674 |
9 | 576465504513441 |
10 | 134020200003004 |
11 | 39780714003057 |
12 | 13046019994a24 |
13 | 59a2087314003 |
14 | 25148801a7180 |
15 | 107628db29ba4 |
hex | 79e40269f5bc |
134020200003004 has 48 divisors (see below), whose sum is σ = 268095589913088. Its totient is φ = 57425403526848.
The previous prime is 134020200002987. The next prime is 134020200003017. The reversal of 134020200003004 is 400300002020431.
It is a super-2 number, since 2×1340202000030042 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5263318377 + ... + 5263343839.
It is an arithmetic number, because the mean of its divisors is an integer number (5585324789856).
Almost surely, 2134020200003004 is an apocalyptic number.
134020200003004 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
134020200003004 is an abundant number, since it is smaller than the sum of its proper divisors (134075389910084).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134020200003004 is a wasteful number, since it uses less digits than its factorization.
134020200003004 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56794 (or 56792 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 19.
Adding to 134020200003004 its reverse (400300002020431), we get a palindrome (534320202023435).
The spelling of 134020200003004 in words is "one hundred thirty-four trillion, twenty billion, two hundred million, three thousand, four".
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