1340204014213 has 4 divisors (see below), whose sum is σ = 1354020550540. Its totient is φ = 1326387477888.

The previous prime is 1340204014211. The next prime is 1340204014297. The reversal of 1340204014213 is 3124104020431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 461031494049 + 879172520164 = 678993^2 + 937642^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340204014213 - 2¹ = 1340204014211 is a prime.

It is a super-2 number, since 2×1340204014213² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340204014211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6908268018 + ... + 6908268211.

It is an arithmetic number, because the mean of its divisors is an integer number (338505137635).

Almost surely, 2^{1340204014213} is an apocalyptic number.

It is an amenable number.

1340204014213 is a deficient number, since it is larger than the sum of its proper divisors (13816536327).

1340204014213 is an equidigital number, since it uses as much as digits as its factorization.

1340204014213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13816536326.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1340204014213 its reverse (3124104020431), we get a palindrome (4464308034644).

The spelling of 1340204014213 in words is "one trillion, three hundred forty billion, two hundred four million, fourteen thousand, two hundred thirteen".