13402040331 has 8 divisors (see below), whose sum is σ = 17908151184. Its totient is φ = 8915311520.

The previous prime is 13402040329. The next prime is 13402040341. The reversal of 13402040331 is 13304020431.

13402040331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13402040331 - 2¹ = 13402040329 is a prime.

It is a super-2 number, since 2×13402040331² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13402040298 and 13402040307.

It is not an unprimeable number, because it can be changed into a prime (13402040341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4843896 + ... + 4846661.

It is an arithmetic number, because the mean of its divisors is an integer number (2238518898).

Almost surely, 2^13402040331 is an apocalyptic number.

13402040331 is a deficient number, since it is larger than the sum of its proper divisors (4506110853).

13402040331 is an equidigital number, since it uses as much as digits as its factorization.

13402040331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9691021.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 13402040331 its reverse (13304020431), we get a palindrome (26706060762).

The spelling of 13402040331 in words is "thirteen billion, four hundred two million, forty thousand, three hundred thirty-one".