Base | Representation |
---|---|
bin | 11000111101101001… |
… | …01111000000010111 |
3 | 1021121000022021221102 |
4 | 30132310233000113 |
5 | 204421410324031 |
6 | 10053512140315 |
7 | 653054323613 |
oct | 143664570027 |
9 | 37530267842 |
10 | 13402042391 |
11 | 57581158a1 |
12 | 272039769b |
13 | 1357779aca |
14 | 911d02343 |
15 | 5368ba7cb |
hex | 31ed2f017 |
13402042391 has 2 divisors, whose sum is σ = 13402042392. Its totient is φ = 13402042390.
The previous prime is 13402042343. The next prime is 13402042469. The reversal of 13402042391 is 19324020431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13402042391 - 218 = 13401780247 is a prime.
It is a super-3 number, since 3×134020423913 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13402042691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701021195 + 6701021196.
It is an arithmetic number, because the mean of its divisors is an integer number (6701021196).
Almost surely, 213402042391 is an apocalyptic number.
13402042391 is a deficient number, since it is larger than the sum of its proper divisors (1).
13402042391 is an equidigital number, since it uses as much as digits as its factorization.
13402042391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
The spelling of 13402042391 in words is "thirteen billion, four hundred two million, forty-two thousand, three hundred ninety-one".
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