13402112314313 has 8 divisors (see below), whose sum is σ = 13466432117160. Its totient is φ = 13337910423040.

The previous prime is 13402112314277. The next prime is 13402112314333. The reversal of 13402112314313 is 31341321120431.

It can be written as a sum of positive squares in 4 ways, for example, as 2235467541904 + 11166644772409 = 1495148^2 + 3341653^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13402112314313 - 2⁴² = 9004065803209 is a prime.

It is a super-2 number, since 2×13402112314313² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13402112314333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29250020 + ... + 29704677.

It is an arithmetic number, because the mean of its divisors is an integer number (1683304014645).

Almost surely, 2^{13402112314313} is an apocalyptic number.

It is an amenable number.

13402112314313 is a deficient number, since it is larger than the sum of its proper divisors (64319802847).

13402112314313 is an equidigital number, since it uses as much as digits as its factorization.

13402112314313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58955787.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13402112314313 its reverse (31341321120431), we get a palindrome (44743433434744).

The spelling of 13402112314313 in words is "thirteen trillion, four hundred two billion, one hundred twelve million, three hundred fourteen thousand, three hundred thirteen".