Base | Representation |
---|---|
bin | 1100001100000110110000… |
… | …1001001100101111001010 |
3 | 1202110020012020202120202210 |
4 | 3003001230021030233022 |
5 | 3224040011223024224 |
6 | 44300502335005550 |
7 | 2552161560025233 |
oct | 303015411145712 |
9 | 52406166676683 |
10 | 13402112314314 |
11 | 42a78930110a9 |
12 | 16055043698b6 |
13 | 762a76b06689 |
14 | 34494695c08a |
15 | 18394672b429 |
hex | c306c24cbca |
13402112314314 has 16 divisors (see below), whose sum is σ = 27457986205440. Its totient is φ = 4358410508640.
The previous prime is 13402112314277. The next prime is 13402112314333. The reversal of 13402112314314 is 41341321120431.
It is a super-2 number, since 2×134021123143142 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27240065434 + ... + 27240065925.
It is an arithmetic number, because the mean of its divisors is an integer number (1716124137840).
Almost surely, 213402112314314 is an apocalyptic number.
13402112314314 is an abundant number, since it is smaller than the sum of its proper divisors (14055873891126).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13402112314314 is a wasteful number, since it uses less digits than its factorization.
13402112314314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54480131405.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 13402112314314 its reverse (41341321120431), we get a palindrome (54743433434745).
The spelling of 13402112314314 in words is "thirteen trillion, four hundred two billion, one hundred twelve million, three hundred fourteen thousand, three hundred fourteen".
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