134021125143 has 24 divisors (see below), whose sum is σ = 202021279200. Its totient is φ = 85454952000.

The previous prime is 134021125111. The next prime is 134021125169. The reversal of 134021125143 is 341521120431.

134021125143 is a `hidden beast` number, since 1 + 3 + 402 + 1 + 1 + 251 + 4 + 3 = 666.

It is not a de Polignac number, because 134021125143 - 2⁵ = 134021125111 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114021125143) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2989393 + ... + 3033893.

It is an arithmetic number, because the mean of its divisors is an integer number (8417553300).

Almost surely, 2^134021125143 is an apocalyptic number.

134021125143 is a deficient number, since it is larger than the sum of its proper divisors (68000154057).

134021125143 is a wasteful number, since it uses less digits than its factorization.

134021125143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59079 (or 59076 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 134021125143 its reverse (341521120431), we get a palindrome (475542245574).

The spelling of 134021125143 in words is "one hundred thirty-four billion, twenty-one million, one hundred twenty-five thousand, one hundred forty-three".