134021153441101 has 2 divisors, whose sum is σ = 134021153441102. Its totient is φ = 134021153441100.

The previous prime is 134021153441041. The next prime is 134021153441111. The reversal of 134021153441101 is 101144351120431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102089906642025 + 31931246799076 = 10103955^2 + 5650774^2 .

It is a cyclic number.

It is not a de Polignac number, because 134021153441101 - 2¹⁵ = 134021153408333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134021153441111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010576720550 + 67010576720551.

It is an arithmetic number, because the mean of its divisors is an integer number (67010576720551).

Almost surely, 2^{134021153441101} is an apocalyptic number.

It is an amenable number.

134021153441101 is a deficient number, since it is larger than the sum of its proper divisors (1).

134021153441101 is an equidigital number, since it uses as much as digits as its factorization.

134021153441101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

The spelling of 134021153441101 in words is "one hundred thirty-four trillion, twenty-one billion, one hundred fifty-three million, four hundred forty-one thousand, one hundred one".