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13402132444203 = 34467377481401
BaseRepresentation
bin1100001100000110110101…
…0101111111010000101011
31202110020020122122021210020
43003001231111333100223
53224040031401203303
644300504334251523
72552162223105036
oct303015525772053
952406218567706
1013402132444203
1142a78a340aa78
12160550b056ba3
13762a7b033c59
143449494bc01d
151839483a5a53
hexc306d57f42b

13402132444203 has 4 divisors (see below), whose sum is σ = 17869509925608. Its totient is φ = 8934754962800.

The previous prime is 13402132444201. The next prime is 13402132444213. The reversal of 13402132444203 is 30244423120431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13402132444203 - 21 = 13402132444201 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13402132444201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2233688740698 + ... + 2233688740703.

It is an arithmetic number, because the mean of its divisors is an integer number (4467377481402).

Almost surely, 213402132444203 is an apocalyptic number.

13402132444203 is a deficient number, since it is larger than the sum of its proper divisors (4467377481405).

13402132444203 is an equidigital number, since it uses as much as digits as its factorization.

13402132444203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4467377481404.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 13402132444203 its reverse (30244423120431), we get a palindrome (43646555564634).

The spelling of 13402132444203 in words is "thirteen trillion, four hundred two billion, one hundred thirty-two million, four hundred forty-four thousand, two hundred three".

Divisors: 1 3 4467377481401 13402132444203