Base | Representation |
---|---|
bin | 1100001100000110110111… |
… | …1111110010010001001111 |
3 | 1202110020021102020221201222 |
4 | 3003001231333302101033 |
5 | 3224040042202313124 |
6 | 44300505405153555 |
7 | 2552162415201131 |
oct | 303015577622117 |
9 | 52406242227658 |
10 | 13402143401039 |
11 | 42a78a9614008 |
12 | 160551285b8bb |
13 | 762a8039c1a3 |
14 | 34494ab31051 |
15 | 18394931c25e |
hex | c306dff244f |
13402143401039 has 2 divisors, whose sum is σ = 13402143401040. Its totient is φ = 13402143401038.
The previous prime is 13402143401021. The next prime is 13402143401051. The reversal of 13402143401039 is 93010434120431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13402143401039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13402143401089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701071700519 + 6701071700520.
It is an arithmetic number, because the mean of its divisors is an integer number (6701071700520).
Almost surely, 213402143401039 is an apocalyptic number.
13402143401039 is a deficient number, since it is larger than the sum of its proper divisors (1).
13402143401039 is an equidigital number, since it uses as much as digits as its factorization.
13402143401039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 35.
The spelling of 13402143401039 in words is "thirteen trillion, four hundred two billion, one hundred forty-three million, four hundred one thousand, thirty-nine".
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