Base | Representation |
---|---|
bin | 10011100000001011010… |
… | …111000110111001100111 |
3 | 11202010100021010122012221 |
4 | 103200023113012321213 |
5 | 133424232410401203 |
6 | 2503404434253211 |
7 | 165553624315405 |
oct | 23401327067147 |
9 | 4663307118187 |
10 | 1340220403303 |
11 | 477425529521 |
12 | 1978b1127207 |
13 | 994c7a28b52 |
14 | 48c1d12a475 |
15 | 24cdee46abd |
hex | 1380b5c6e67 |
1340220403303 has 2 divisors, whose sum is σ = 1340220403304. Its totient is φ = 1340220403302.
The previous prime is 1340220403283. The next prime is 1340220403387. The reversal of 1340220403303 is 3033040220431.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1340220403303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340220403903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670110201651 + 670110201652.
It is an arithmetic number, because the mean of its divisors is an integer number (670110201652).
Almost surely, 21340220403303 is an apocalyptic number.
1340220403303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340220403303 is an equidigital number, since it uses as much as digits as its factorization.
1340220403303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 1340220403303 its reverse (3033040220431), we get a palindrome (4373260623734).
The spelling of 1340220403303 in words is "one trillion, three hundred forty billion, two hundred twenty million, four hundred three thousand, three hundred three".
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