Base | Representation |
---|---|
bin | 10011100000001011011… |
… | …110111010110110111111 |
3 | 11202010100101222200022120 |
4 | 103200023132322312333 |
5 | 133424233421414020 |
6 | 2503404550214023 |
7 | 165553650604641 |
oct | 23401336726677 |
9 | 4663311880276 |
10 | 1340222451135 |
11 | 4774266a8047 |
12 | 1978b1954313 |
13 | 994c8294c99 |
14 | 48c1d500891 |
15 | 24ce01ed740 |
hex | 1380b7badbf |
1340222451135 has 16 divisors (see below), whose sum is σ = 2180700938880. Its totient is φ = 702670301600.
The previous prime is 1340222451131. The next prime is 1340222451151. The reversal of 1340222451135 is 5311542220431.
It is not a de Polignac number, because 1340222451135 - 22 = 1340222451131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1340222451096 and 1340222451105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340222451131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 757186941 + ... + 757188710.
It is an arithmetic number, because the mean of its divisors is an integer number (136293808680).
Almost surely, 21340222451135 is an apocalyptic number.
1340222451135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1340222451135 is a deficient number, since it is larger than the sum of its proper divisors (840478487745).
1340222451135 is a wasteful number, since it uses less digits than its factorization.
1340222451135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1514375718.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 1340222451135 its reverse (5311542220431), we get a palindrome (6651764671566).
The spelling of 1340222451135 in words is "one trillion, three hundred forty billion, two hundred twenty-two million, four hundred fifty-one thousand, one hundred thirty-five".
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