13402244410033 has 4 divisors (see below), whose sum is σ = 13471686091108. Its totient is φ = 13332802728960.

The previous prime is 13402244410007. The next prime is 13402244410039. The reversal of 13402244410033 is 33001444220431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4404596256369 + 8997648153664 = 2098713^2 + 2999608^2 .

It is a cyclic number.

It is not a de Polignac number, because 13402244410033 - 2⁴¹ = 11203221154481 is a prime.

It is a super-2 number, since 2×13402244410033² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13402244409977 and 13402244410004.

It is not an unprimeable number, because it can be changed into a prime (13402244410039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34720840248 + ... + 34720840633.

It is an arithmetic number, because the mean of its divisors is an integer number (3367921522777).

Almost surely, 2^{13402244410033} is an apocalyptic number.

It is an amenable number.

13402244410033 is a deficient number, since it is larger than the sum of its proper divisors (69441681075).

13402244410033 is an equidigital number, since it uses as much as digits as its factorization.

13402244410033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69441681074.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 13402244410033 its reverse (33001444220431), we get a palindrome (46403688630464).

The spelling of 13402244410033 in words is "thirteen trillion, four hundred two billion, two hundred forty-four million, four hundred ten thousand, thirty-three".