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13402320000000 = 21035755843
BaseRepresentation
bin1100001100000111100010…
…0001011101010000000000
31202110020201201120002222020
43003001320201131100000
53224040422410000000
644300535114241440
72552166661232661
oct303017041352000
952406651502866
1013402320000000
1142a798a273468
121605561a26280
13762aaab52009
14344966381368
15183959aa2ba0
hexc307885d400

13402320000000 has 352 divisors, whose sum is σ = 44653271624832. Its totient is φ = 3573888000000.

The previous prime is 13402319999969. The next prime is 13402320000023. The reversal of 13402320000000 is 2320431.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 239972079 + ... + 240027921.

Almost surely, 213402320000000 is an apocalyptic number.

13402320000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13402320000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22326635812416).

13402320000000 is an abundant number, since it is smaller than the sum of its proper divisors (31250951624832).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13402320000000 is an frugal number, since it uses more digits than its factorization.

13402320000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55901 (or 55853 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 15.

Adding to 13402320000000 its reverse (2320431), we get a palindrome (13402322320431).

The spelling of 13402320000000 in words is "thirteen trillion, four hundred two billion, three hundred twenty million", and thus it is an aban number.