Base | Representation |
---|---|
bin | 11000111101101100… |
… | …00111001011011001 |
3 | 1021121000222122100111 |
4 | 30132312013023121 |
5 | 204422003403140 |
6 | 10053524004321 |
7 | 653060356546 |
oct | 143666071331 |
9 | 37530878314 |
10 | 13402403545 |
11 | 5758342173 |
12 | 27205306a1 |
13 | 13578752cb |
14 | 911d97bcd |
15 | 53693c7ea |
hex | 31ed872d9 |
13402403545 has 4 divisors (see below), whose sum is σ = 16082884260. Its totient is φ = 10721922832.
The previous prime is 13402403473. The next prime is 13402403561. The reversal of 13402403545 is 54530420431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54530420431 = 457 ⋅119322583.
It can be written as a sum of positive squares in 2 ways, for example, as 4576928409 + 8825475136 = 67653^2 + 93944^2 .
It is a cyclic number.
It is not a de Polignac number, because 13402403545 - 223 = 13394014937 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1340240350 + ... + 1340240359.
It is an arithmetic number, because the mean of its divisors is an integer number (4020721065).
Almost surely, 213402403545 is an apocalyptic number.
It is an amenable number.
13402403545 is a deficient number, since it is larger than the sum of its proper divisors (2680480715).
13402403545 is an equidigital number, since it uses as much as digits as its factorization.
13402403545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2680480714.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 13402403545 its reverse (54530420431), we get a palindrome (67932823976).
The spelling of 13402403545 in words is "thirteen billion, four hundred two million, four hundred three thousand, five hundred forty-five".
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