1340241213132 has 144 divisors (see below), whose sum is σ = 3461121664000. Its totient is φ = 437177917440.

The previous prime is 1340241213119. The next prime is 1340241213197. The reversal of 1340241213132 is 2313121420431.

1340241213132 is a `hidden beast` number, since 1 + 3 + 402 + 4 + 121 + 3 + 132 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 1340241213096 and 1340241213105.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 369108957 + ... + 369112587.

Almost surely, 2^{1340241213132} is an apocalyptic number.

1340241213132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1340241213132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1730560832000).

1340241213132 is an abundant number, since it is smaller than the sum of its proper divisors (2120880450868).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340241213132 is a wasteful number, since it uses less digits than its factorization.

1340241213132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4676 (or 4671 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 1340241213132 its reverse (2313121420431), we get a palindrome (3653362633563).

The spelling of 1340241213132 in words is "one trillion, three hundred forty billion, two hundred forty-one million, two hundred thirteen thousand, one hundred thirty-two".