13402414401 has 4 divisors (see below), whose sum is σ = 17869885872. Its totient is φ = 8934942932.

The previous prime is 13402414393. The next prime is 13402414439. The reversal of 13402414401 is 10441420431.

13402414401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13402414401 - 2³ = 13402414393 is a prime.

It is a super-2 number, since 2×13402414401² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13402415401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2233735731 + ... + 2233735736.

It is an arithmetic number, because the mean of its divisors is an integer number (4467471468).

Almost surely, 2^13402414401 is an apocalyptic number.

It is an amenable number.

13402414401 is a deficient number, since it is larger than the sum of its proper divisors (4467471471).

13402414401 is an equidigital number, since it uses as much as digits as its factorization.

13402414401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4467471470.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 13402414401 its reverse (10441420431), we get a palindrome (23843834832).

The spelling of 13402414401 in words is "thirteen billion, four hundred two million, four hundred fourteen thousand, four hundred one".