134024440113001 has 2 divisors, whose sum is σ = 134024440113002. Its totient is φ = 134024440113000.

The previous prime is 134024440112999. The next prime is 134024440113007. The reversal of 134024440113001 is 100311044420431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123432988801600 + 10591451311401 = 11110040^2 + 3254451^2 .

It is a cyclic number.

It is not a de Polignac number, because 134024440113001 - 2¹ = 134024440112999 is a prime.

Together with 134024440112999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (134024440113007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67012220056500 + 67012220056501.

It is an arithmetic number, because the mean of its divisors is an integer number (67012220056501).

Almost surely, 2^{134024440113001} is an apocalyptic number.

It is an amenable number.

134024440113001 is a deficient number, since it is larger than the sum of its proper divisors (1).

134024440113001 is an equidigital number, since it uses as much as digits as its factorization.

134024440113001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 134024440113001 its reverse (100311044420431), we get a palindrome (234335484533432).

The spelling of 134024440113001 in words is "one hundred thirty-four trillion, twenty-four billion, four hundred forty million, one hundred thirteen thousand, one".