1340255350429 has 4 divisors (see below), whose sum is σ = 1345200942400. Its totient is φ = 1335309758460.

The previous prime is 1340255350403. The next prime is 1340255350439. The reversal of 1340255350429 is 9240535520431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340255350429 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340255350439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2472795579 + ... + 2472796120.

It is an arithmetic number, because the mean of its divisors is an integer number (336300235600).

Almost surely, 2^{1340255350429} is an apocalyptic number.

It is an amenable number.

1340255350429 is a deficient number, since it is larger than the sum of its proper divisors (4945591971).

1340255350429 is an equidigital number, since it uses as much as digits as its factorization.

1340255350429 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4945591970.

The product of its (nonzero) digits is 648000, while the sum is 43.

The spelling of 1340255350429 in words is "one trillion, three hundred forty billion, two hundred fifty-five million, three hundred fifty thousand, four hundred twenty-nine".