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1340305035353 = 8017316717661
BaseRepresentation
bin10011100000010000011…
…001111101000001011001
311202010120011101101120022
4103200100121331001121
5133424421042112403
62503421100240225
7165556002553154
oct23402031750131
94663504341508
101340305035353
11477469283869
12197915540075
139950c41b69b
1448c2a47ac9b
1524ce75b2d38
hex1381067d059

1340305035353 has 4 divisors (see below), whose sum is σ = 1340321833188. Its totient is φ = 1340288237520.

The previous prime is 1340305035347. The next prime is 1340305035367. The reversal of 1340305035353 is 3535305030431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 702114953929 + 638190081424 = 837923^2 + 798868^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340305035353 - 210 = 1340305034329 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340305035313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8278658 + ... + 8439003.

It is an arithmetic number, because the mean of its divisors is an integer number (335080458297).

Almost surely, 21340305035353 is an apocalyptic number.

It is an amenable number.

1340305035353 is a deficient number, since it is larger than the sum of its proper divisors (16797835).

1340305035353 is an equidigital number, since it uses as much as digits as its factorization.

1340305035353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16797834.

The product of its (nonzero) digits is 121500, while the sum is 35.

The spelling of 1340305035353 in words is "one trillion, three hundred forty billion, three hundred five million, thirty-five thousand, three hundred fifty-three".

Divisors: 1 80173 16717661 1340305035353