Base | Representation |
---|---|
bin | 1100001100001010100101… |
… | …1101110000010100001101 |
3 | 1202110022211221121222101120 |
4 | 3003002221131300110031 |
5 | 3224044113111104401 |
6 | 44301152405431153 |
7 | 2552226221462505 |
oct | 303025135602415 |
9 | 52408757558346 |
10 | 13403141113101 |
11 | 42a8270814933 |
12 | 1605750a0b4b9 |
13 | 762babcb7b5c |
14 | 344a03444a05 |
15 | 1839a6bea836 |
hex | c30a977050d |
13403141113101 has 16 divisors (see below), whose sum is σ = 18655917895680. Its totient is φ = 8543232094320.
The previous prime is 13403141113093. The next prime is 13403141113171. The reversal of 13403141113101 is 10131114130431.
It is not a de Polignac number, because 13403141113101 - 23 = 13403141113093 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13403141113171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41867461 + ... + 42186378.
It is an arithmetic number, because the mean of its divisors is an integer number (1165994868480).
Almost surely, 213403141113101 is an apocalyptic number.
It is an amenable number.
13403141113101 is a deficient number, since it is larger than the sum of its proper divisors (5252776782579).
13403141113101 is a wasteful number, since it uses less digits than its factorization.
13403141113101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84056176.
The product of its (nonzero) digits is 432, while the sum is 24.
Adding to 13403141113101 its reverse (10131114130431), we get a palindrome (23534255243532).
The spelling of 13403141113101 in words is "thirteen trillion, four hundred three billion, one hundred forty-one million, one hundred thirteen thousand, one hundred one".
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