1340321240041 has 8 divisors (see below), whose sum is σ = 1531913339264. Its totient is φ = 1148758549920.

The previous prime is 1340321239993. The next prime is 1340321240077. The reversal of 1340321240041 is 1400421230431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340321240041 - 2²⁵ = 1340287685609 is a prime.

It is a super-2 number, since 2×1340321240041² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1340321239988 and 1340321240015.

It is not an unprimeable number, because it can be changed into a prime (1340321240441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7254525 + ... + 7436986.

It is an arithmetic number, because the mean of its divisors is an integer number (191489167408).

Almost surely, 2^{1340321240041} is an apocalyptic number.

It is an amenable number.

1340321240041 is a deficient number, since it is larger than the sum of its proper divisors (191592099223).

1340321240041 is a wasteful number, since it uses less digits than its factorization.

1340321240041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14704551.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1340321240041 its reverse (1400421230431), we get a palindrome (2740742470472).

The spelling of 1340321240041 in words is "one trillion, three hundred forty billion, three hundred twenty-one million, two hundred forty thousand, forty-one".