1340321240077 has 2 divisors, whose sum is σ = 1340321240078. Its totient is φ = 1340321240076.

The previous prime is 1340321239993. The next prime is 1340321240099. The reversal of 1340321240077 is 7700421230431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1333900262916 + 6420977161 = 1154946^2 + 80131^2 .

It is an emirp because it is prime and its reverse (7700421230431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340321240077 - 2¹¹ = 1340321238029 is a prime.

It is a super-2 number, since 2×1340321240077² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340321240177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670160620038 + 670160620039.

It is an arithmetic number, because the mean of its divisors is an integer number (670160620039).

Almost surely, 2^{1340321240077} is an apocalyptic number.

It is an amenable number.

1340321240077 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340321240077 is an equidigital number, since it uses as much as digits as its factorization.

1340321240077 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28224, while the sum is 34.

The spelling of 1340321240077 in words is "one trillion, three hundred forty billion, three hundred twenty-one million, two hundred forty thousand, seventy-seven".