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1340321241014 = 27176784053759
BaseRepresentation
bin10011100000010001010…
…111110001011110110110
311202010121021212201112222
4103200101113301132312
5133424434214203024
62503422435442342
7165556260400040
oct23402127613666
94663537781488
101340321241014
11477477442378
1219791aa563b2
13995128a3a32
1448c2c698a90
1524ce8c1485e
hex138115f17b6

1340321241014 has 32 divisors (see below), whose sum is σ = 2469163253760. Its totient is φ = 532564610688.

The previous prime is 1340321241001. The next prime is 1340321241071. The reversal of 1340321241014 is 4101421230431.

It is a super-2 number, since 2×13403212410142 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42010934 + ... + 42042825.

It is an arithmetic number, because the mean of its divisors is an integer number (77161351680).

Almost surely, 21340321241014 is an apocalyptic number.

1340321241014 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

1340321241014 is a deficient number, since it is larger than the sum of its proper divisors (1128842012746).

1340321241014 is a wasteful number, since it uses less digits than its factorization.

1340321241014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84053852.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 1340321241014 its reverse (4101421230431), we get a palindrome (5441742471445).

The spelling of 1340321241014 in words is "one trillion, three hundred forty billion, three hundred twenty-one million, two hundred forty-one thousand, fourteen".

Divisors: 1 2 7 14 17 34 67 119 134 238 469 938 1139 2278 7973 15946 84053759 168107518 588376313 1176752626 1428913903 2857827806 5631601853 10002397321 11263203706 20004794642 39421212971 78842425942 95737231501 191474463002 670160620507 1340321241014