Base | Representation |
---|---|
bin | 1100001100001010110111… |
… | …0111101000001100100010 |
3 | 1202110100001002200001021012 |
4 | 3003002231313220030202 |
5 | 3224044241020120300 |
6 | 44301204005300522 |
7 | 2552231106524255 |
oct | 303025567501442 |
9 | 52410032601235 |
10 | 13403215004450 |
11 | 42a82a94a3567 |
12 | 1605771704742 |
13 | 762bc13b994b |
14 | 344a0d19b09c |
15 | 1839ad444435 |
hex | c30adde8322 |
13403215004450 has 48 divisors (see below), whose sum is σ = 25069828868736. Its totient is φ = 5331286641600.
The previous prime is 13403215004411. The next prime is 13403215004453. The reversal of 13403215004450 is 5440051230431.
It is a super-2 number, since 2×134032150044502 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13403215004453) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6140984 + ... + 8032316.
It is an arithmetic number, because the mean of its divisors is an integer number (522288101432).
Almost surely, 213403215004450 is an apocalyptic number.
13403215004450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13403215004450 is a deficient number, since it is larger than the sum of its proper divisors (11666613864286).
13403215004450 is a wasteful number, since it uses less digits than its factorization.
13403215004450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1892139 (or 1892134 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 13403215004450 its reverse (5440051230431), we get a palindrome (18843266234881).
The spelling of 13403215004450 in words is "thirteen trillion, four hundred three billion, two hundred fifteen million, four thousand, four hundred fifty".
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