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134033166602341 is a prime number
BaseRepresentation
bin11110011110011100000111…
…010010001001000001100101
3122120120110000211111221212021
4132132130013102021001211
5120031444411122233331
61153021553043223141
740142401550164336
oct3636340722110145
9576513024457767
10134033166602341
1139786168345056
1213048638377ab1
1359a33727bcbb6
14251535031a28d
15107679c180211
hex79e707489065

134033166602341 has 2 divisors, whose sum is σ = 134033166602342. Its totient is φ = 134033166602340.

The previous prime is 134033166602333. The next prime is 134033166602371. The reversal of 134033166602341 is 143206661330431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99391348969441 + 34641817632900 = 9969521^2 + 5885730^2 .

It is a cyclic number.

It is not a de Polignac number, because 134033166602341 - 23 = 134033166602333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134033166602371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67016583301170 + 67016583301171.

It is an arithmetic number, because the mean of its divisors is an integer number (67016583301171).

Almost surely, 2134033166602341 is an apocalyptic number.

It is an amenable number.

134033166602341 is a deficient number, since it is larger than the sum of its proper divisors (1).

134033166602341 is an equidigital number, since it uses as much as digits as its factorization.

134033166602341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 559872, while the sum is 43.

The spelling of 134033166602341 in words is "one hundred thirty-four trillion, thirty-three billion, one hundred sixty-six million, six hundred two thousand, three hundred forty-one".