13403380411301 has 4 divisors (see below), whose sum is σ = 14108821485600. Its totient is φ = 12697939337004.

The previous prime is 13403380411283. The next prime is 13403380411321. The reversal of 13403380411301 is 10311408330431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13403380411301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13403380411321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352720537121 + ... + 352720537158.

It is an arithmetic number, because the mean of its divisors is an integer number (3527205371400).

Almost surely, 2^{13403380411301} is an apocalyptic number.

It is an amenable number.

13403380411301 is a deficient number, since it is larger than the sum of its proper divisors (705441074299).

13403380411301 is an equidigital number, since it uses as much as digits as its factorization.

13403380411301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 705441074298.

The product of its (nonzero) digits is 10368, while the sum is 32.

Adding to 13403380411301 its reverse (10311408330431), we get a palindrome (23714788741732).

The spelling of 13403380411301 in words is "thirteen trillion, four hundred three billion, three hundred eighty million, four hundred eleven thousand, three hundred one".