Base | Representation |
---|---|
bin | 11110011110011101000001… |
… | …010100111001101001001111 |
3 | 122120120112112200220020000121 |
4 | 132132131001110321221033 |
5 | 120032003404420414203 |
6 | 1153022233431205411 |
7 | 40142434643313166 |
oct | 3636350124715117 |
9 | 576515480806017 |
10 | 134034140404303 |
11 | 39786617aa4967 |
12 | 1304886a516867 |
13 | 59a3499486789 |
14 | 25154037a83dd |
15 | 10768078d90bd |
hex | 79e741539a4f |
134034140404303 has 2 divisors, whose sum is σ = 134034140404304. Its totient is φ = 134034140404302.
The previous prime is 134034140404277. The next prime is 134034140404357. The reversal of 134034140404303 is 303404041430431.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134034140404303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134034140404903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67017070202151 + 67017070202152.
It is an arithmetic number, because the mean of its divisors is an integer number (67017070202152).
Almost surely, 2134034140404303 is an apocalyptic number.
134034140404303 is a deficient number, since it is larger than the sum of its proper divisors (1).
134034140404303 is an equidigital number, since it uses as much as digits as its factorization.
134034140404303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 134034140404303 its reverse (303404041430431), we get a palindrome (437438181834734).
The spelling of 134034140404303 in words is "one hundred thirty-four trillion, thirty-four billion, one hundred forty million, four hundred four thousand, three hundred three".
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