13403444341303 has 16 divisors (see below), whose sum is σ = 14134801449600. Its totient is φ = 12690292975360.

The previous prime is 13403444341223. The next prime is 13403444341333. The reversal of 13403444341303 is 30314344430431.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13403444341303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13403444341333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 545283 + ... + 5206171.

It is an arithmetic number, because the mean of its divisors is an integer number (883425090600).

Almost surely, 2^{13403444341303} is an apocalyptic number.

13403444341303 is a deficient number, since it is larger than the sum of its proper divisors (731357108297).

13403444341303 is a wasteful number, since it uses less digits than its factorization.

13403444341303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4662842.

The product of its (nonzero) digits is 248832, while the sum is 37.

Adding to 13403444341303 its reverse (30314344430431), we get a palindrome (43717788771734).

The spelling of 13403444341303 in words is "thirteen trillion, four hundred three billion, four hundred forty-four million, three hundred forty-one thousand, three hundred three".