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13403453451 = 34467817817
BaseRepresentation
bin11000111101110100…
…00111100000001011
31021121002221222112220
430132322013200023
5204422241002301
610054002305123
7653102321523
oct143672074013
937532858486
1013403453451
115758999a63
1227209581a3
131357b5215b
1491218c683
15536a98936
hex31ee8780b

13403453451 has 4 divisors (see below), whose sum is σ = 17871271272. Its totient is φ = 8935635632.

The previous prime is 13403453411. The next prime is 13403453473. The reversal of 13403453451 is 15435430431.

13403453451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13403453451 - 221 = 13401356299 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13403453411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2233908906 + ... + 2233908911.

It is an arithmetic number, because the mean of its divisors is an integer number (4467817818).

Almost surely, 213403453451 is an apocalyptic number.

13403453451 is a deficient number, since it is larger than the sum of its proper divisors (4467817821).

13403453451 is an equidigital number, since it uses as much as digits as its factorization.

13403453451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4467817820.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 13403453451 its reverse (15435430431), we get a palindrome (28838883882).

The spelling of 13403453451 in words is "thirteen billion, four hundred three million, four hundred fifty-three thousand, four hundred fifty-one".

Divisors: 1 3 4467817817 13403453451