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13403468437 is a prime number
BaseRepresentation
bin11000111101110100…
…01011001010010101
31021121002222202002221
430132322023022111
5204422241442222
610054002502341
7653102413312
oct143672131225
937532882087
1013403468437
1157589aa247
1227209649b1
131357b58c18
14912193d09
15536a9d0c7
hex31ee8b295

13403468437 has 2 divisors, whose sum is σ = 13403468438. Its totient is φ = 13403468436.

The previous prime is 13403468387. The next prime is 13403468453. The reversal of 13403468437 is 73486430431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12858199236 + 545269201 = 113394^2 + 23351^2 .

It is a cyclic number.

It is not a de Polignac number, because 13403468437 - 211 = 13403466389 is a prime.

It is a super-2 number, since 2×134034684372 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13403468393 and 13403468402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13403438437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701734218 + 6701734219.

It is an arithmetic number, because the mean of its divisors is an integer number (6701734219).

Almost surely, 213403468437 is an apocalyptic number.

It is an amenable number.

13403468437 is a deficient number, since it is larger than the sum of its proper divisors (1).

13403468437 is an equidigital number, since it uses as much as digits as its factorization.

13403468437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 580608, while the sum is 43.

Adding to 13403468437 its reverse (73486430431), we get a palindrome (86889898868).

The spelling of 13403468437 in words is "thirteen billion, four hundred three million, four hundred sixty-eight thousand, four hundred thirty-seven".